Finding the min value of an expression

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SUMMARY

The problem involves finding the minimum value of the expression a² + b² + c² + d² given the constraint ab + bc + cd + da = 16. The solution utilizes differential calculus and the properties of squares, leading to the conclusion that the minimum occurs when a = b = c = d = 2, resulting in a minimum value of 16. The approaches discussed include manipulating the expression using inequalities and applying the concept of fixed area rectangles to derive the solution.

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Homework Statement


[itex]a,b,c,d[/itex] are real numbers
[itex]ab+bc+cd+da=16[/itex]
Find the minimum value possible for [itex]a²+b²+c²+d²[/itex]


Homework Equations


[itex]ab+bc+cd+da = (a+c)(b+d)[/itex]
[itex]x^2 \ge 0[/itex] for some real x

The Attempt at a Solution


1st approach:[itex]2(a^2 +b^2 +c^2 +d^2) + 2(ab+bc+cd+da)[/itex] [tex]= (a+b)^2 +(b+c)^2 +(c+d)^2 +(d+a)^2 \ge 0[/tex]
which gives [itex]a^2 +b^2 +c^2 +d^2 \ge -16[/itex] that cannot give the min. value.

2nd approach: [itex](a+c)(b+d) =16[/itex]
By differential calculus, rectangle of fixed area has min. diagonal when it is square,
[itex]a+c=b+d=4[/itex]
[itex]a=b=c=d=2[/itex]
[itex]a^2 +b^2 +c^2 +d^2 \ge 2^2+2^2+2^2+2^2 =16[/itex]

How would you solve this? If you think there is any unclear reasonings in my post or others' replies please do not mind elaborating/criticizing/replacing them for me and others.
 
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Your first approach is good, but try subtracting instead of adding. Then you can demonstrate (as you have) that the lowest answer is achievable.
 

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