Finding the number of spheres in a graduated cylinder

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To find the number of spheres in a graduated cylinder with a minimum volume of 40 mL, the volume of each sphere is calculated to be 0.0477 cm³. Using the close packing fraction of 0.74048, it is determined that 29.6 cm³ of the total volume is effectively occupied by the spheres, with 10.4 cm³ as wasted space. Dividing the effective volume by the volume of a sphere yields approximately 621 spheres. This calculation confirms the correct application of the close packing fraction to account for wasted space. The final conclusion is that there are 621 spheres in the cylinder.
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Homework Statement



This is from a worksheet. I had to find the volume myself

"A large number of spheres are poured into a graduated cylinder and gently vibrated until the occupy a minimum volume of 40 mL (or 40 cm^3). Use the information about close packing and the data you found to find the number of spheres in the cylinder. "

I found -- volume = 0.0477 cm^3
diameter = 4.5 mm
Given -- close packing fraction = .74048


Homework Equations



Wasn't given one but I used (minimum volume) / (volume of a sphere)


The Attempt at a Solution



40 cm^3 / 0.0477 cm^3 = 839 spheres



I'm not sure if I did was right. I don't know what I'm supposed to do with the information about the close packing fraction. I can't find it in my book.
 
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brotivation said:

Homework Statement



This is from a worksheet. I had to find the volume myself

"A large number of spheres are poured into a graduated cylinder and gently vibrated until the occupy a minimum volume of 40 mL (or 40 cm^3). Use the information about close packing and the data you found to find the number of spheres in the cylinder. "

I found -- volume = 0.0477 cm^3
diameter = 4.5 mm
Given -- close packing fraction = .74048

Homework Equations



Wasn't given one but I used (minimum volume) / (volume of a sphere)

The Attempt at a Solution



40 cm^3 / 0.0477 cm^3 = 839 spheres

I'm not sure if I did was right. I don't know what I'm supposed to do with the information about the close packing fraction. I can't find it in my book.

What does the close packing fraction tell you?
 
It tells me that 26% of the used volume is wasted space.
 
brotivation said:
It tells me that 26% of the used volume is wasted space.

So, isn't 26% of the 40 cm3 volume, wasted space?
 
SammyS said:
So, isn't 26% of the 40 cm3 volume, wasted space?

Okay, so this is what I did.

40 cm^3 * .74048 = 29.6 cm^3

29.6 cm^3 / .0477 cm^3 = 621 spheres

Is this right?

10.4 cm^3 of the 40 cm^3 is wasted space leaving 29.6 cm^3 being used. So I would take the used value and divided by the volume of the sphere right?
 
brotivation said:
Okay, so this is what I did.

40 cm^3 * .74048 = 29.6 cm^3

29.6 cm^3 / .0477 cm^3 = 621 spheres

Is this right?

10.4 cm^3 of the 40 cm^3 is wasted space leaving 29.6 cm^3 being used. So I would take the used value and divided by the volume of the sphere right?
That seems reasonable !
 
SammyS said:
That seems reasonable !

Thanks a lot. It hit me right when I saw you said 26% lol.
 

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