Finding the period of trig series analytically?

AI Thread Summary
To calculate the period of a trigonometric series analytically, one must determine the individual periods of each component function. For the example x(t)=5sin(16t)-4cos(8t+3.1), the periods are found to be π/4 and π/8, which are commensurable, allowing for a clear calculation of the overall period. In contrast, for the function x(t)=4sin(15t)-3cos(9t+1.1), the calculated period is approximately 2.1, but the exact analytical period requires finding the least common multiple of the individual periods. This is feasible if the ratio of the periods is a rational number, meaning they are commensurable. Understanding the relationship between the periods of the functions is crucial for accurate calculations.
gongo88
Messages
3
Reaction score
0
Is there a way to calculate the period of a trigonometric series (like the one below) analytically?

x(t)=5sin(16t)-4cos(8t+3.1)
 
Mathematics news on Phys.org
The period in this case can be gotten from: 8t = 2π or t = π/4. This works since the other term has a period 16t = 2π or t = π/8 which is a harmonic.
 
Sorry, I'm still confused. For this example...

x(t)=4sin(15t)-3cos(9t+1.1)

...I have graphed this in MATLAB, and graphically found a period of about 2.1. I am trying to apply what you suggested, but can't figure out how to calculate the period of 2.1...
 

Attachments

  • ex.png
    ex.png
    20.1 KB · Views: 548
The sum of two periodic functions will be periodic it the two periods are commensurable. That means the ratio of their periods is a rational number. And in that case, the period is the least common multiple of the individual periods. For non-integers p and q, the LCM is the least number z such that ap = z and bq = z for a and b integers.

.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads

Back
Top