Finding the phase angle of a pendulum swinging.

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SUMMARY

The discussion focuses on calculating the phase angle of a second pendulum in a system where two identical pendulums have the same amplitude and length of 20 cm. At time t = 0, the first pendulum is at +6 cm, while the second pendulum has a velocity of -27 cm/s and is positioned at the opposite end of the equilibrium. To find the phase angle of the second pendulum, one must determine its position at time t = 0 using the relationship between position, amplitude, and phase angle in simple harmonic motion.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Knowledge of pendulum dynamics
  • Familiarity with phase angle concepts in oscillatory systems
  • Ability to apply kinematic equations to harmonic motion
NEXT STEPS
  • Study the equations of motion for simple harmonic oscillators
  • Learn how to derive phase angles from position and velocity data
  • Explore the mathematical relationships between amplitude, frequency, and phase in pendulums
  • Investigate the effects of initial conditions on pendulum motion
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Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators looking for examples of pendulum dynamics and phase angle calculations.

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Homework Statement



The question reads:

Two identical pendulums have the same amplitude and the same length (20cm) At time t = 0, one pendulum reaches the end of its swing at x = +6 cm. At the same time the second pendulum has velocity v = -27 cm/s and sits on opposite ends of the equilibrium position. Find the phase angle of the second pendulum.


Homework Equations





The Attempt at a Solution



Ive tried several things but I am hung up on finding the position of the 2nd pendulum at time 0.
 
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Can you show what you have tried?
 

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