Finding the potential difference between 2 points in a circuit

[ellieee]

Homework Statement

nil

Relevant Equations

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is this method accepted?
2V is split equally between the 2 5kohms resistor because they are of equal resistance.
2V=5kohms
2kohms= 0.8V
3kohms=1.2V.
p.d across P and Q= 1V-0.8V=0.2V

 

[Bystander]

See also "Wheatstone Bridge."

 

[phinds]

You've left out a step that one would normally want to include on a test (show HOW you got 1.2v and .8v using current, but certainly you have the right answer and, I think, the right idea.

 

[Delta2]

You have left out two steps in my opinion.

The first step is as indicated by @phinds too at post #3, you need to show why the voltage splits to 0.8 and 1.2V given that the resistors are $2k\Omega$ and $3k\Omega$.

The second step, which might be scrutiny, however I consider it necessary is if we call O the upper end of resistor of $5k\Omega$ and R the upper end of resistor of $2k\Omega$ and given that $V_{OP}=1V$ and $V_{RQ}=0.8V$ to prove that $V_{QP}=0.2V$, and given of course that $V_{OR}=0$ since points O and R are connected with a conductor of zero resistance. This step is also related to whether the problem want us to find $V_{PQ}$ or $V_{QP}$. It turns out that $V_{PQ}=-0.2V$!

 

[ellieee]

why the voltage splits to 0.8 and 1.2V given that the resistors are 2kΩ and 3kΩ.

2V=5kohms
2kohms= 0.8V
3kohms=1.2V.
p.d across P and Q= 1V-0.8V=0.2V
is this explanation not sufficient ?

 

[Delta2]

2V=5kohms
2kohms= 0.8V
3kohms=1.2V.
p.d across P and Q= 1V-0.8V=0.2V
is this explanation not sufficient ?

It is mostly correct but omits many intermediate steps, outlined in my post #4. If I was your grader I might have cut you up to 40% of the total points.
Tell me how did you calculate that the voltage of 2V splits to 0,8V and 1.2V?

 

[phinds]

2V=5kohms
2kohms= 0.8V
3kohms=1.2V.
p.d across P and Q= 1V-0.8V=0.2V
is this explanation not sufficient ?

No, as we keep telling you, you are leaving out steps. Yes, you got the right answer but you could have been guessing for all one can tell from that statement.