- #1

- 78

- 6

- Homework Statement
- nil

- Relevant Equations
- nil

is this method accepted?

2V is split equally between the 2 5kohms resistor because they are of equal resistance.

2V=5kohms

2kohms= 0.8V

3kohms=1.2V.

p.d across P and Q= 1V-0.8V=0.2V

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- Thread starter ellieee
- Start date

It would have been nice if you had explained what you did to get the right answer.In summary, the method accepted in this conversation involves splitting 2V equally between the two 5kohm resistors, resulting in 0.8V and 1.2V across the 2kohm and 3kohm resistors, respectively. The potential difference across points P and Q is then calculated as 0.2V. However, this explanation does not include all the necessary steps for a complete understanding.

- #1

- 78

- 6

- Homework Statement
- nil

- Relevant Equations
- nil

is this method accepted?

2V is split equally between the 2 5kohms resistor because they are of equal resistance.

2V=5kohms

2kohms= 0.8V

3kohms=1.2V.

p.d across P and Q= 1V-0.8V=0.2V

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- #2

Science Advisor

Homework Helper

Gold Member

- 5,547

- 1,630

See also "Wheatstone Bridge."

- #3

- 18,625

- 12,696

- #4

- 5,695

- 2,477

The first step is as indicated by @phinds too at post #3, you need to show why the voltage splits to 0.8 and 1.2V given that the resistors are ##2k\Omega## and ##3k\Omega##.

The second step, which might be scrutiny, however I consider it necessary is if we call O the upper end of resistor of ##5k\Omega## and R the upper end of resistor of ##2k\Omega## and given that ##V_{OP}=1V## and ##V_{RQ}=0.8V## to prove that ##V_{QP}=0.2V##, and given of course that ##V_{OR}=0## since points O and R are connected with a conductor of zero resistance. This step is also related to whether the problem want us to find ##V_{PQ}## or ##V_{QP}##. It turns out that ##V_{PQ}=-0.2V##!

- #5

- 78

- 6

2V=5kohmsDelta2 said:why the voltage splits to 0.8 and 1.2V given that the resistors are 2kΩ and 3kΩ.

2kohms= 0.8V

3kohms=1.2V.

p.d across P and Q= 1V-0.8V=0.2V

is this explanation not sufficient ?

- #6

- 5,695

- 2,477

It is mostly correct but omits many intermediate steps, outlined in my post #4. If I was your grader I might have cut you up to 40% of the total points.ellieee said:2V=5kohms

2kohms= 0.8V

3kohms=1.2V.

p.d across P and Q= 1V-0.8V=0.2V

is this explanation not sufficient ?

Tell me how did you calculate that the voltage of 2V splits to 0,8V and 1.2V?

- #7

- 18,625

- 12,696

No, as we keep telling you, you are leaving out steps. Yes, you got the right answer but you could have been guessing for all one can tell from that statement.ellieee said:2V=5kohms

2kohms= 0.8V

3kohms=1.2V.

p.d across P and Q= 1V-0.8V=0.2V

is this explanation not sufficient ?

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