Finding the Power Series of f(x) = 10/(1-5x)

ganondorf29
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Homework Statement


Determine the series of the given function:

f(x) = 10 / (1-5*x)

Homework Equations



Power series of 1/(1-x) = Σ from n=0 to n=infinity of (x^n)

The Attempt at a Solution



f(x) = 10/(1-5x)
= 10*(1/1-5x)
= 10 * Σ(5x)^n
= 10 * Σ(5^n)*(x^n)
= Σ (50^n)*(x^n) <--- Not sure if that is right

Any help would be appreciated. Thank you
 
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Not right. The series part is fine. But 10*(5^n) does not equal 50^n. Think about, say, n=2.
 
Is it just Σ(5^n)*(x^n)*10 ?
 
I think that's the simplest way to write it, yes.
 
One more thing. To find the interval on convergence, I know I have to take the ratio test as n-->infinity. Is this how I'm supposed to set it up?

lim [x^(n+1) * 5^(n+1) / (n+1)*(n+1)] * [(n*n/x^n*5^x)]
n->inf

After canceling out some factors I got:

lim 1/(2n+1) = 0
n->inf

Is that right?
 
No. Where are all those n+1 and n's coming from? The nth term of your series a_n=10*5^n*x^n. So the ratio of a_(n+1)/a_n is just 10*5^(n+1)*x^(n+1)/(10*5^n*x^n) isn't it? What's that?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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