- #1
cheezeitz
- 8
- 0
Homework Statement
y' = csc2([tex]\vartheta[/tex] / 2 )
Find y"
The Attempt at a Solution
So far, i have 2 csc ([tex]\vartheta[/tex]/2) *csc([tex]\vartheta[/tex]/2)cot([tex]\vartheta[/tex]/2) * 1/2
but I'm wondering, how do you take the derivative of a half angle identity?
or does it just simplify down to csc2([tex]\vartheta[/tex] / 2) * cot([tex]\vartheta[/tex]/2)