Finding the shared area of 2 polar equations

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SUMMARY

The discussion focuses on finding the shared area between two polar equations: r=5-3cos(θ) and r=5-2sin(θ). The correct approach involves equating the two equations to determine the limits of integration, which are θ=π/4 and θ=5π/4. The area can be calculated using the formula A=1/2∫ r^2 dθ, leading to the integrals A = ∫(5−3cos(θ))^2 dθ and A = ∫(5−2sin(θ))^2 dθ for the respective curves.

PREREQUISITES
  • Understanding of polar coordinates and equations
  • Knowledge of integral calculus, specifically area under curves
  • Familiarity with the limaçon shape in polar graphs
  • Ability to solve trigonometric equations
NEXT STEPS
  • Study the derivation of the area formula A=1/2∫ r^2 dθ in polar coordinates
  • Learn how to find intersection points of polar curves
  • Explore the properties of limaçon curves and their applications
  • Practice solving integrals involving trigonometric functions in polar coordinates
USEFUL FOR

Students studying calculus, particularly those focusing on polar coordinates and area calculations, as well as educators looking for examples of polar integration techniques.

shortman12012
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Homework Statement



Given the two polar equations r=5-3cos(θ) and r=5-2sin(θ) find the area of the region common to both curves.


Homework Equations



A= 1/2∫ r^2 dθ

The Attempt at a Solution


i understand that i plug in the two equations into the equation, but i don't know how to find the limits of integration.
 
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To find the limits of the integral, equate the equations, so set:
[tex] 5-3\cos\theta =5-2\sin\theta[/tex]
This will give two values of theta for your limits.
 
correction it should be 5-3cosθ =5-3sinθ, but after equating those two and solving i got
θ=π/4,5π/4
so now would the correct integral for solving the shared area of the two limaçon
A = ∫(5−3cos(θ))^2 dθ + ∫(5−2sin(θ))^2 dθ ?
 

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