Finding the Speed of Rain in Relative Motion

AI Thread Summary
The discussion revolves around a relative motion problem involving a man walking and rain falling at different angles. Initially, the man walks at 2 km/h, perceiving the rain to fall vertically, but when he doubles his speed, the rain appears to fall at a 30-degree angle. Participants suggest using vector triangles to analyze the velocities of the man and the rain, emphasizing that the rain's velocity relative to the ground remains constant. There is confusion regarding the interpretation of the rain's direction and the correct application of trigonometric functions to solve for the rain's actual speed. The conversation highlights the importance of accurately representing vector relationships in relative motion problems.
kalupahana
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Relative motion prob, please help

Homework Statement


A man walk at a rate of 2 km/h; A rain appears to fall vertically. when he doubled his speed it appears to fall at 30o vertical. Find the real speed of the rain.


Homework Equations





The Attempt at a Solution


Help me to do this question. I cannot understand what my teacher said about relative motion. Please explain me how find the answer for this question.
 
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hi kalupahana! :wink:

let VMG be the velocity of the Man relative to the Ground,
VRG be the velocity of the Rain relative to the Ground,
and VRM be the velocity of the Rain relative to the Man

then draw a vector triangle MRG for each of the two situations: the length of the RG side will be the same in both triangles, and the length of the MG side will be 2 in one triangle and 4 in the other triangle :smile:

(see the pf library entry on vector triangle for some more details)
 


tiny-tim said:
hi kalupahana! :wink:

let VMG be the velocity of the Man relative to the Ground,
VRG be the velocity of the Rain relative to the Ground,
and VRM be the velocity of the Rain relative to the Man

then draw a vector triangle MRG for each of the two situations: the length of the RG side will be the same in both triangles, and the length of the MG side will be 2 in one triangle and 4 in the other triangle :smile:

(see the pf library entry on vector triangle for some more details)

In both instance VRM is constant.
then sin60 = 2/x

x = 4/√3 = 2.3 km/h

is this right
 
kalupahana said:
In both instance VRM is constant.

No, VRG is constant (it's the same Rain, so its velocity relative to the Ground is the same).

Try again … draw the two triangles, with a shared side …

what does it look like? :smile:
 


tiny-tim said:
No, VRG is constant (it's the same Rain, so its velocity relative to the Ground is the same).

Try again … draw the two triangles, with a shared side …

what does it look like? :smile:

I got triangle like this

then tan60 = VRG /4
4√3 = VRG
 

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hi kalupahana! :smile:

(just got up :zzz: …)

That's the right idea, but you've misinterpreted the question.

Your diagram show the rain falling vertically, but it doesn't.

Also, your arrows are going the wrong way round each vector triangle …

they have to match up so that VRG = VRM + VMG

(or VRM = VRG + VGM = VRG - VMG).

Try again. :smile:
 
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