Finding the sum of an infinite series

jspectral
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Homework Statement


\sum\frac{1}{n2^(n+1)} from 1 to infinity.

By the way, that 2 is to the power of (n+1), doesn't show clearly.

Homework Equations


The Attempt at a Solution


I have worked out the first few individual calculations, up to n=6, and i know it approaches ln(2)/2, however I have no idea how to actually prove this.
 
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What sorts of theorems do you know about power series?
 
jbunniii said:
What sorts of theorems do you know about power series?

A few, it's for a 2nd year university subject. We've been using proof by induction a fair bit, but other than that I don't know the actual names for them.
 
What do you know of integrating power series?
 
TheFurryGoat said:
What do you know of integrating power series?

You mean int(1 + x + x^2 + x^3 + ...) = x + x^2/2 + x^3/3 + ... ?
 
jspectral said:
You mean int(1 + x + x^2 + x^3 + ...) = x + x^2/2 + x^3/3 + ... ?

Yes. See if you can work out how to apply that property to your problem.

(Hint: start by replacing the "1/2" with a variable.)

By the way, you can click on the following equation if you want to see how to typeset the sum properly:

\sum_{n=1}^{\infty}\frac{1}{n 2^{n+1}}
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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