Finding the Sum of Two Numbers When Their Product is 1,000

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To find two whole numbers x and y such that their product is 1,000 and neither has 10 as a factor, it is determined that one number must end in 5 while the other must be even. This leads to the expressions x = 2a and y = 10b + 5, where a is a non-zero integer and b can be zero. By substituting these expressions into the product equation xy = 1,000, the problem can be simplified to find suitable values for a and b. The discussion emphasizes the necessity of these conditions to ensure the product meets the criteria. Ultimately, the solution involves solving the resulting equations to find the sum x + y.
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If x and y are whole numbers that don't have10 as a factor, and if xy = 1,000, find x + y.
 
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You have 2 integers x and y such that their product xy is a multiple of 10, but neither x nor y is a multiple of 10 (the rightmost digit of the product is 0).

Then the rightmost digit of one of them, let's say y, must be 5, and then x must be an even number. Think about it and you will see that this is the only way to end up with 0 in the 1's column of the product.

So you can express x and y in a different form:
x = 2a
y = 10b + 5
where a is a non-zero integer and b is an integer (maybe 0).

Now, find the product in terms of a and b, set that equal to 1000 & see if that helps you find the answer.
 
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The steps.

The answer with the steps to follow.
 
I edited my post. See hints above.
 
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