Finding the tension of a support cable to balance the beam

Click For Summary
To find the tension in the support cable balancing the beam, the correct approach involves calculating the torques around the fulcrum. The downward gravitational force on the beam and the upward force from the cable must be balanced. The center of mass (COM) of the system is crucial, calculated as 1.28 m based on the masses and their distances from the fulcrum. The equation for torques must account for the weights and their respective distances from the fulcrum to solve for the tension. Ultimately, the tension in the cable is determined to be 170 N.
JohnTheGreat101
Messages
8
Reaction score
0
Homework Statement
Find the tension in the support cable needed to balance the beam
Relevant Equations
0=tc + tbl - tbr - tcyl
I know the answer is 170 but I am not sure how to get there. I tried doing things backwards
g=9.8
t = fr = mgr
0= 170 + tbl - tbr - 5x9.8x1.5
0= 170 + tbl - tbr - 73.5
-96.5 = tbl - tbr
-96.5 = 18*9.8 * 0.2 - 18*9.8*1.4
-96.5 does not equal -211.68
 

Attachments

  • physics problem find tension.PNG
    physics problem find tension.PNG
    8.6 KB · Views: 146
Physics news on Phys.org
Hint: Where's the center of mass of the beam?
 
Ok so I found the mass of the cable. mgr/gr = m
170/9.8x1.2 = 14.46 kg.
COM = 5 kg x 1.5m + 14.46 kg x 1.2 / 14.46 + 5 = 1.28 m
 
There are three forces acting on the beam that create torques about the fulcrum:
  • The downward force of gravity on the beam. (Where does it act?)
  • The upward force of the cable. (Which is what you are trying to find.)
  • The downward force of the cylinder's weight on the beam.
Add up the torques due to these forces.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
5K
  • · Replies 2 ·
Replies
2
Views
19K
Replies
1
Views
6K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
4
Views
2K