Finding the tension of a support cable to balance the beam

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SUMMARY

The tension of a support cable required to balance a beam is calculated to be 170 N. The gravitational constant used is 9.8 m/s². The center of mass (COM) of the system is determined to be 1.28 m, factoring in the weights of both the beam and the cable. The analysis involves balancing the torques created by the downward force of gravity on the beam, the upward force of the cable, and the downward force of the cylinder's weight.

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JohnTheGreat101
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Homework Statement
Find the tension in the support cable needed to balance the beam
Relevant Equations
0=tc + tbl - tbr - tcyl
I know the answer is 170 but I am not sure how to get there. I tried doing things backwards
g=9.8
t = fr = mgr
0= 170 + tbl - tbr - 5x9.8x1.5
0= 170 + tbl - tbr - 73.5
-96.5 = tbl - tbr
-96.5 = 18*9.8 * 0.2 - 18*9.8*1.4
-96.5 does not equal -211.68
 

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Hint: Where's the center of mass of the beam?
 
Ok so I found the mass of the cable. mgr/gr = m
170/9.8x1.2 = 14.46 kg.
COM = 5 kg x 1.5m + 14.46 kg x 1.2 / 14.46 + 5 = 1.28 m
 
There are three forces acting on the beam that create torques about the fulcrum:
  • The downward force of gravity on the beam. (Where does it act?)
  • The upward force of the cable. (Which is what you are trying to find.)
  • The downward force of the cylinder's weight on the beam.
Add up the torques due to these forces.
 

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