Finding the volume of a cone with a elliptic base

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To find the volume of a cone with an elliptical base, the area of the ellipse is calculated using the formula (pi)ab, where a and b are the lengths of the semimajor and semiminor axes. For a cone with height h = 20 and base axes a = 4 and b = 6, the volume can be determined using the formula V = (1/3) * pi * a * b * h. The initial attempt involved using similar triangles to derive the area at various cross-sections, but the user expressed confusion over their failure to integrate correctly. However, the correct volume can be directly computed as (1/3) * pi * 4 * 6 * 20, confirming the setup was accurate. The discussion emphasizes the importance of understanding both geometric properties and integration techniques in solving such problems.
Ahlahn
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Finding the volume of a cone with a elliptic base!

Homework Statement



The area of an ellipse is (pi)ab, where a and b are the lengths of the semimajor and semiminor axes. Compute the volume of a cone of height h = 20 whose base is an ellipse with semimajor and semiminor axes a = 4 and b = 6.

Homework Equations


The Attempt at a Solution



I tried to use the law of similar triangles to obtain the area of the elliptic at the cross section.

4/20 = a/20-y and 6/20 = b/20-y
b=6(20-y)/20 and a = 4(20-y)/20

Since the area of an elliptic is (pi)a*b, I tried to integrate by plugging in the above equations for a and b on the interval [0,20]. I failed.

HELP!
 
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You've set up the problem exactly correctly. The volume is (1/3)*pi*a*b where a=4 and b=6. The integral also gives you (1/3)*pi*a*b where a=4 and b=6. How exactly did you 'fail'?
 
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