1. The problem statement, all variables and given/known data I know how to find the volume of a sphere just by adding the areas of circles, so I decided to do a double integral to find the same volume, just for fun. Here's what I've set up. I put 8 out front and designed the integrals to find an eighth of a sphere that has its center at the origin. This piece of the sphere is what you would get if you cut a sphere in half three times, one from each of the three dimensions. 8∫01∫0√(1-y2)√(1-x2-y2)dxdy √(1-x2-y2) is the equation I used to measure the z-dimension of a point on the sphere given values for x and y. 2. Relevant equations 3. The attempt at a solution Here's the integral I got for the inner integration, the one with respect to x: ∫0√(1-y2)√(1-x2-y2)dx =[-2x/(2√(1-x2-y2))] with 0 on the bottom and √(1-y2) on the top. As you can see, if I plug in √(1-y2) for x, the values cancel out so that there is only a zero in the denominator. Is this simply a limitation in using multiple integration, or did I do something wrong? Any help is appreciated.