First Law of Thermodynamics help

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The discussion centers on applying the First Law of Thermodynamics to a scenario involving steam flow into an insulated enclosure. The user is confused about the variables in the energy equation, particularly regarding the initial mass of steam (m1) being zero and the velocity terms. They assert that heat transfer (Q) and work (W) are both zero due to the insulated nature of the system. Clarification is sought on the relationship between mass flow rates (mIN and m2) and the significance of the indices used in the equation. Understanding these concepts is crucial for solving the problem effectively.
lecammm
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Homework Statement



Steam flow through a pipe at a pressure if 8bar and a temperature of 340C. A valve is opened and steam is allow to enter an insulated enclosure whose volume is 0.5(m^3), until the pressure equals the quantity of steam that enters the enclosure.


Homework Equations



Q - W + ∑MIN(hIN+(v2IN)/2+gzIN) - ∑mOUT(hOUT+(v2OUT)/2+gzOUT) = m2(u2+(v22)/2+gz2) - m1(u1+(v21)/2+gz1)

The Attempt at a Solution



(Here is where I'm not sure)

I know that:

gz = 0 for all

And I would have thought that because up until the pressure in the chamber is equivalent to the mass of the steam, mOUT would be zero, as the steam is only coming in.

I also THINK that Q is 0 because no heat is being added to the system, and W is zero because there is no mechanical reactions.

However, what I don't understand is the answer says that m1 is 0 (why? Is this because the only input is mIN?), vIN is 0 (is this because of the equivalence of v1 and vIN?)

The next step in the solution is

mINhIN = m2u2

And is it right that mIN and m2 will be equivalent based of continuity?

Thanks for any help as I am alright with using steam tables and interpolation later
 
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There is no question in the problem statement.
In your relevant equation, I observed two different kind of indices:

IN and OUT
1 and 2

What does that all mean?
An equation without meaning is useless.

Do not expect to solve a problem that you cannot expose properly, or that you do not understand.
 

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