First Law of Thermodynamics help

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SUMMARY

The discussion revolves around the application of the First Law of Thermodynamics to a steam flow problem involving an insulated enclosure. The scenario describes steam entering a 0.5 m³ volume at 8 bar and 340°C, with the participant attempting to apply the energy balance equation. Key points include the assumption that heat transfer (Q) and work (W) are both zero, leading to the conclusion that the mass flow in (mIN) equals the internal energy change (m2u2). The participant seeks clarification on why initial mass (m1) is considered zero and the implications of velocity terms in the equation.

PREREQUISITES
  • Understanding of the First Law of Thermodynamics
  • Familiarity with steam properties and steam tables
  • Knowledge of energy balance equations in thermodynamics
  • Basic concepts of fluid dynamics, particularly mass flow rates
NEXT STEPS
  • Study the derivation and application of the First Law of Thermodynamics in closed systems
  • Learn how to use steam tables for calculating properties of steam at various pressures and temperatures
  • Explore the concept of mass continuity in fluid flow and its implications in thermodynamic systems
  • Investigate the significance of kinetic and potential energy terms in energy balance equations
USEFUL FOR

Students and professionals in mechanical engineering, particularly those focusing on thermodynamics and fluid mechanics, will benefit from this discussion.

lecammm
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Homework Statement



Steam flow through a pipe at a pressure if 8bar and a temperature of 340C. A valve is opened and steam is allow to enter an insulated enclosure whose volume is 0.5(m^3), until the pressure equals the quantity of steam that enters the enclosure.


Homework Equations



Q - W + ∑MIN(hIN+(v2IN)/2+gzIN) - ∑mOUT(hOUT+(v2OUT)/2+gzOUT) = m2(u2+(v22)/2+gz2) - m1(u1+(v21)/2+gz1)

The Attempt at a Solution



(Here is where I'm not sure)

I know that:

gz = 0 for all

And I would have thought that because up until the pressure in the chamber is equivalent to the mass of the steam, mOUT would be zero, as the steam is only coming in.

I also THINK that Q is 0 because no heat is being added to the system, and W is zero because there is no mechanical reactions.

However, what I don't understand is the answer says that m1 is 0 (why? Is this because the only input is mIN?), vIN is 0 (is this because of the equivalence of v1 and vIN?)

The next step in the solution is

mINhIN = m2u2

And is it right that mIN and m2 will be equivalent based of continuity?

Thanks for any help as I am alright with using steam tables and interpolation later
 
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There is no question in the problem statement.
In your relevant equation, I observed two different kind of indices:

IN and OUT
1 and 2

What does that all mean?
An equation without meaning is useless.

Do not expect to solve a problem that you cannot expose properly, or that you do not understand.
 

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