First order differential equation help

xman
Messages
92
Reaction score
0
i've derived the following differential eqn from a problem I'm working on, and i have tried in vain to solve this if anyone can give a direction where i should go our how to attack would be greatly appreciated. the eqn is

I\,r= -L\dot{I}+\frac{3}{2}\mu_{0}m R^{2}\frac{z \dot{z}}{\left(R^{2}+z^{2}\right)^{5/2}}

where r,L,m,\mu_{0},R,\dot{z} are all constants. one of two ways I've tried solving this, was since
\dot{z}=const.\Rightarrow z=\dot{z}t
which just gives a particular solution i cannot find a solution for. the homogeneous part is quite trivial with the solution being
I_{homogeneous}=const. \, \exp(-rt/L)
am i missing something, is there another way. any help please
 
Physics news on Phys.org
If L = 0, then if r = 0, I can be anything. If r is not zero, then I is just the right side divided by r. So we may assume L is nonzero. Let A = 1.5μ0mR²(z'³L)-1, B = R/z', D = r/L

I' + DI = At/(B² + t²)5/2

The solution to the homogenous equation is, as you know IH = Ce-rt/L. So you just need a particular solution. See if this helps at all.
 
thanks for the cite reference, i checked it out, and it's similar information i have in my old ode book in front of me. the integral you get with this
\int e^{Dt}\frac{At}{(B^{2}+t^{2})^{5/2}}dt
doesn't seem to be able to be integrated. i think this particular ode might need numerical methods to solve.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top