First-Order Transients: Steady-State DC Response

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The discussion revolves around analyzing a circuit with a current source, inductor, and capacitor to find the DC current in the inductor and the DC voltage across the capacitor. Participants clarify that at steady state, the inductor acts as a short circuit and the capacitor as an open circuit, leading to a simplified analysis. Various methods are suggested for calculating the voltage across the capacitor and the current through the inductor, including using voltage and current divider rules. The final consensus indicates that the voltage across the capacitor is 1V, and the inductor carries the entire current from the source, which is 3A. The conversation emphasizes the importance of circuit topology and careful application of circuit analysis techniques.
  • #31
dudforreal said:
I thought the voltage across the capacitor must be the same as the voltage across R2.

Well, you asked, so I thought perhaps you were contemplating other thoughts on the matter.

The circuit diagram clearly shows that at steady state the capacitor is effectively in parallel with R2 (the inductor is a short).
 
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  • #32
...so the capacitor voltage is 1V?
 
  • #33
dudforreal said:
...so the capacitor voltage is 1V?

Do you have a better suggestion?

{I have to say that I don't like providing answers to questions framed as guesses; they're too much like fishing for a result rather than understanding. I tend to turn such questions back on the poser automatically. Sorry if it seems brusk.}
 

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