Flat plate, circular hole center of mass

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Homework Help Overview

The discussion revolves around calculating the x-coordinate of the center of mass of a uniform flat plate with a circular hole. The plate is described as a rectangle with specific dimensions, and the circular hole has a defined radius and position within the rectangle.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate formula for calculating the center of mass, questioning whether to use mass or area in the calculations. There are inquiries about how to account for the circular hole and its effect on the overall mass.

Discussion Status

Participants are actively engaging with each other's questions and clarifications, exploring the implications of using area instead of mass when density is not provided. There is a focus on ensuring that all coordinates are measured from the same origin, and some participants are verifying their understanding of the center of mass calculations.

Contextual Notes

There is a mention of a lack of explicit density information, which influences the approach to calculating mass. Additionally, some confusion exists regarding the dimensions and positions of the shapes involved, indicating a need for clearer visual representation.

gap0063
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Homework Statement


A uniform flat plate of metal with a circular hole, where it is a rectangle starting from -6 to 7 from the length, and the height is -3 to 3.

The circle has a radius of 2, and it starts at 1 to 5.
Calculate the x-coordinate of the center of
mass xcm of the metal plate.


Homework Equations


well Xcm= m1x1+m2x2/m1+m2


The Attempt at a Solution



is this the right equation?
and if so, how do I take out the circular part?
 
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hi gap0063! :wink:
gap0063 said:
well Xcm= m1x1+m2x2/m1+m2

is this the right equation?

yes :smile:
and if so, how do I take out the circular part?

it has negative mass! :biggrin:

(no, seriously, it really does … try it!)
 
tiny-tim said:
hi gap0063! :wink:


yes :smile:


it has negative mass! :biggrin:

(no, seriously, it really does … try it!)


this is probably a dumb question, but how do you find the mass of the rectangle and circle?

and is the x1 and x2 the coordinates?
 
hi gap0063! :smile:
gap0063 said:
this is probably a dumb question, but how do you find the mass of the rectangle and circle?

and is the x1 and x2 the coordinates?

if you're not given the density, then use area instead of mass in the formula

and yes, x1 and x2 are the x coordinates of the centre of mass and of the hole respectively (and similarly for y1 and y2) :wink:
 
tiny-tim said:
hi gap0063! :smile:


if you're not given the density, then use area instead of mass in the formula

and yes, x1 and x2 are the x coordinates of the centre of mass and of the hole respectively (and similarly for y1 and y2) :wink:

alright, is this right:

13*6(1/2)-(7)(22\Pi/ (13*6+ 4\Pi)
 
hi gap0063! :smile:

(have a pi: π :wink:)

gap0063 said:
alright, is this right:

13*6(1/2)-(7)(22\Pi/ (13*6+ 4\Pi)

for the total mass (on the bottom) you need minus 4π, don't you? :wink:

apart from that, it looks ok, except i don't understand where the (7) comes from

(and i didn't understand what this meant :confused: …)
gap0063 said:
The circle … starts at 1 to 5.
 
tiny-tim said:
hi gap0063! :smile:

(have a pi: π :wink:)



for the total mass (on the bottom) you need minus 4π, don't you? :wink:

apart from that, it looks ok, except i don't understand where the (7) comes from

(and i didn't understand what this meant :confused: …)


Yes I meant minus on the bottom


the 7 is from how far away the cicle is from the begin on the rectangle

sorry I don't have the picture but the shapes are on a coordinate system and inside the rectangle (that goes from (-6,0) to (7,0) ) the circle lies at (1,0) to (5,0).
 
so the centre of the circle is at (3,0)?

ok, then you must use x2 = 3 …

your x1 x2 and x must all be measured from the same origin :wink:
 
tiny-tim said:
so the centre of the circle is at (3,0)?

ok, then you must use x2 = 3 …

your x1 x2 and x must all be measured from the same origin :wink:

yes the center of the circle is (3,0)

so what is x1...? is it 1/2?
 
  • #10
yes, your x1 = 1/2 was correct :smile:
 

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