Flex Your Mathletic Muscles Impress the Ladies

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The discussion revolves around solving the differential equation y' = k * y^(1/2). The original poster admits to forgetting the solution techniques and seeks help from others to impress women in the forum. A participant points out that the equation is separable and provides the solution as y = (k*x/2 + C)^2, emphasizing the importance of including a constant. The original poster acknowledges the oversight and expresses embarrassment for not recalling the method sooner. The conversation highlights both the challenge of solving differential equations and the social dynamics within the forum.
eNtRopY
A few days ago in the physics board, we encountered the following differential equation of the form:

y' = k * y^(1/2).

It's been a long time since I've taken a class in the techniques of solving differential equation, and I can't remember off-hand how to solve this problem. Rather than research the method for solving this problem myself, I thought I'd give you dudes a chance to impress all the beautiful ladies on these boards (e.g. Entropia, Kerrie, Galatea, Kat, Monique, Saint, etc.).

eNtRopY

P.S. If you are a lady, and I have forgotten you, I'm sorry... I don't have a very good memory for names.
 
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In other words, you're lazy and you want us to do your work for you. :smile:

This equation is seperable:

dy/dx = k * y^(1/2)

y^(-1/2) * dy = k * dx
 
Lazy... or too busy?
Anyway,

y = (k*x/2 + C)^2

Thanks... I don't know why I didn't see that right away. I guess I should be embarrassed.

eNtRopY
 
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Originally posted by eNtRopY
Lazy... or too busy?
Anyway,

y = (k*x/2)^2

Thanks... I don't know why I didn't see that right away. I guess I should be embarrassed.

eNtRopY

You forgot to add a constant before squaring.
 
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