- #1
zetafunction
- 391
- 0
does the floor function satisfy
[tex] floor(x)= x + O(x^{1/2}) [/tex]
the idea is the floor function would have an 'smooth' part given by x and a oscillating contribution with amplitude proportional to [tex] x^{1/2} [/tex]
[tex] floor(x)= x + O(x^{1/2}) [/tex]
the idea is the floor function would have an 'smooth' part given by x and a oscillating contribution with amplitude proportional to [tex] x^{1/2} [/tex]