grscott_2000
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The forum discussion addresses the calculation of fluid velocity given a flow rate of 5 m³/s and a pipe diameter of 0.6 m. The correct formula to determine velocity is derived from the relationship between flow rate and cross-sectional area, leading to the conclusion that the velocity is 17.68 m/s. The discussion clarifies that the initial miscalculation arose from an incorrect radius used in the formula. The correct application of the formula, including the proper handling of the diameter and radius, yields consistent and accurate results.
PREREQUISITESEngineers, physics students, and professionals in fluid mechanics who require accurate calculations of fluid velocity and flow rates in piping systems.
No, if the diameter of the pipe is .6 m then its radius is .6/2= .3 m.grscott_2000 said:The problem..
I have been given a flow rate in units of m^3 per second. I also know the diameter of the pipe the fluid is flowing in meters.
I have to calculate the velocity of the flow and give the answer in units of ms^-1
Relevant values..
pipe diameter = 0.6m
flow rate = 5 m^3 per second
My answer...
I know that
flow rate = cross sectional area x velocity
So all things considered I should just be able to rearrange the equation to give
velocity = flow rate / area = 5 / (pi * .15 * .15) = 70.7 ms-1
Yes, this is exactly the same thing: diameter= 2*radius so (diameter)^2= 4*radius. Canceling the "4" in the numerator and denominator gives exactly what you have above.Second point...
I also know that
velocity = 4 * flow rate / (pi * (pipe diameter)^2)
Although you have the correct answer, there is a typo on the left: "pi" should not be squared.Which gives a completely different answer...
(4 * 5) / ((pi * 0.6)^2) = 17.68 ms-1
I would very much appreciate anyone who can help me out with this apparent annomily. I tend to think that the second point is correct because I can plug various values into it, rearrange etc and still get a sensible answer