Rate of flow - thermal physics

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Kathhhriine
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Homework Statement
"The temperature difference between the inlet and the outlet of an air-cooled engine is 30.0 K. The engine generates 7.0 kW of waste power that the air extracts from the engine. Calculate the rate of flow of air (in kg s–1) needed to extract this power. Specifc heat capacity of air (at constant pressure)
= 1.01 × 10^3 J kg–1 K–1 "
Relevant Equations
power/specific heat capacityXtemperautre
Frankly, i don't even know how to start this. I deducted from the solution, that they must have used power/(specific heat capacity x temperautre), however i don't understand how that will give the rate of flow of air. Could anybody help, please?
 
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Kathhhriine said:
Frankly, i don't even know how to start this.
Isn't good enough: we are not allowed to help if you don't post your own attempt

https://www.physicsforums.com/threads/homework-help-guidelines-for-students-and-helpers.686781/

Kathhhriine said:
pressure/specific heat capacityXtemperautre
What on Earth is that for an equation ?

Kathhhriine said:
Homework Statement:: "The temperature difference between the inlet and the outlet of an air-cooled engine is 30.0 K. The engine generates 7.0 kW of waste power that the air extracts from the engine. Calculate the rate of flow of air (in kg s–1) needed to extract this power. Specifc heat capacity of air (at constant pressure)
= 1.01 × 103 J kg–1 K–1 "
Try to re-formulate this in your own words, clearly separating the givens from the results asked for

Kathhhriine said:
Specifc heat capacity of air (at constant pressure)
= 1.01 × 103 J kg–1 K–1 "
You mean 1.01 kJ/(kg.K) ?

There is a subscript button under
1606825108486.png
in the edit window toolbar
Kathhhriine said:
I deducted from the solution, that they must have used pressure/(specific heat capacity x temperautre)
unlikely: pressure isn't mentioned in the problem statement.

Kathhhriine said:
how that will give the rate of flow of air
Have you done other exercises before ? Call the flow F (kg/s) and manipulate the relevant equation until you have F = ... :smile:
 
BvU said:
Isn't good enough: we are not allowed to help if you don't post your own attempt

https://www.physicsforums.com/threads/homework-help-guidelines-for-students-and-helpers.686781/

What on Earth is that for an equation ?

Try to re-formulate this in your own words, clearly separating the givens from the results asked for

You mean 1.01 kJ/(kg.K) ?

There is a subscript button under View attachment 273489 in the edit window toolbarunlikely: pressure isn't mentioned in the problem statement.

Have you done other exercises before ? Call the flow F (kg/s) and manipulate the relevant equation until you have F = ... :smile:

I meant power, where i wrote pressure, sorry. :oops:
 
BvU said:
Try to re-formulate this (the problem statement) in your own words, clearly separating the givens from the results asked for
Another tip: look carefully at the units