Fluid Displacement and the Drop in Water Level Explained

AI Thread Summary
When the anchor is in the boat, it displaces a volume of water equal to its weight, causing the water level to rise. Once the anchor is dropped into the pool, it displaces a volume of water equal to its own volume, which is less than the volume displaced when it was in the boat due to its higher density. This results in a net decrease in the water level. The confusion arises from the difference between weight displacement and volume displacement. Ultimately, the water level drops because the anchor displaces less water when submerged than when it was in the boat.
vu10758
Messages
95
Reaction score
0

Homework Statement


A small child floats in a boat in a swimming pool. The boat contains an anchor
The child drops the metal anchor into the water and watches it sink to the bottom. Meanwhile, the water level in the pool (measured by its height on the side of the pool) actually drops. Why?

Homework Equations





The Attempt at a Solution



I am thinking that if the anchor is dropped into the water, the water should rise because of Archimedes principle. However, I am told that the water level actually drop. Where did the water go? Is it because as the boat pushes down on the water, the water pushes the boat further up due to Newton's third law, causing it to appear as if the water level has dropped? Or is the reason something else? I know that the change in pressure is the same as the weight of the boat so does this have anything to do with the question?
 
Physics news on Phys.org
Think about the mass of the anchor and its volume. When the anchor is in the water what volume of water does it displace? When the anchor is in the boat what volume of water does it displace?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top