Fluid Mechanics and hydraulic lever

AI Thread Summary
In a hydraulic lever system with two ideal fluid-lined cylinders, the output force is 100 times greater than the input force. For 1 Joule of work done on the input side, the output work remains 1 Joule, as simple machines do not change the total amount of work, only the force's magnitude or direction. The discussion highlights the application of Pascal's principle, which states that pressure is distributed evenly throughout the fluid. Participants express confusion about the problem's completeness and seek clarification on the output work calculation. Ultimately, the conversation underscores the fundamental principle that work input equals work output in ideal systems.
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Homework Statement


In a hydraulic lever consisting of two ideal fluid lined cylinder/pistons with a fluid filled line coupling the two cylinders, the output force is 100 times the input force. For 1 Joule of work done on the input side, the work done on the output side is (in J):

Homework Equations


AV=AV
Pressure is distributed evenly (Pascal's principle).

The Attempt at a Solution


I have no clue how to proceed.
This is what I had in mind.

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Last edited:
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You question seems incomplete (and is missing combinations of the letters 'fl' for some reason). What are you trying to find?
 
Oops, good point. I am trying to find the output work - the work done by the output cylinder.
 
Is it true that simple machines do not change the amount of work done but only change the magnitude and/or the direction of the force applied? Because if so that makes this problem extremely easy.
 
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