Fluid Mechanics - Drag (Bending Moment)

Click For Summary

Discussion Overview

The discussion revolves around calculating the drag force and bending moment on a mast due to wind. It involves applying principles of fluid mechanics and structural analysis, specifically focusing on the effects of wind load on a vertical structure.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents a problem involving a mast subjected to wind, providing initial calculations for drag force using the drag equation.
  • Another participant suggests that the drag force can be treated as a uniformly distributed load along the mast, proposing a method to calculate the bending moment based on this assumption.
  • A later reply expresses self-doubt about the initial question posed, indicating a perceived lack of understanding.
  • Further interaction includes a light-hearted acknowledgment of the assistance provided.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method for calculating the bending moment, as the initial poster expresses uncertainty about the approach suggested by others.

Contextual Notes

The discussion does not clarify the assumptions regarding load distribution or the validity of the bending moment calculation method proposed.

Who May Find This Useful

Students or individuals interested in fluid mechanics, structural analysis, or those seeking assistance with similar engineering problems.

MrWinesy
Messages
9
Reaction score
0
A television transmitting antenna is placed on top of a mast which is 30m high and 300mm in diameter. The mast is on top of a tall building. The wind blows at 35m/s and at normal atmospheric pressure (1.225kg/m^3). If the drag coefficient for the mast is 0.2. calculate:

(i) the total drag force on the mast.
(ii) the bending moment at the base of the mast.

(i) Fd=.5*Cd*ρ*U^2*A=.5*.2*1.225*35^2*(30*0.3)=1350.6N

(ii) but how do you do this question?

(the answer is M=20.26kNm but i do not know how to get there)

thank you in advance for your help.
 
Physics news on Phys.org
I think they're assuming the drag force is an even distributed load over the entire mast. With that as the case, you can place the 1350.6 N force at the midpoint of the mast (15m). The FBD yields 1350.6 N * 15m = 20259 Nm.
 
that was potentially the most stupid question i have ever asked. thanks for your help sir.
 
Hahaha you're welcome. Glad I could help.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
19K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 25 ·
Replies
25
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 14 ·
Replies
14
Views
5K