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Please see attached. I'm pretty sure i did the problem right, but I'd like to check with the great minds of physicsforums.

Summing up flow rates and inlet and outlet gives:

1500+1200=2700 gal/min

2700gal/min= area at exit *Velocity at exit

2700 gal/min * (1ft^3 / 7.48 gal) ( 1min / 60 s) = Area at exit * 30 ft/2

Area=0.2 ft^3 or 1.5 gallons

Summing up flow rates and inlet and outlet gives:

1500+1200=2700 gal/min

2700gal/min= area at exit *Velocity at exit

2700 gal/min * (1ft^3 / 7.48 gal) ( 1min / 60 s) = Area at exit * 30 ft/2

Area=0.2 ft^3 or 1.5 gallons