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Fluid Mechanics Open Channel Problem

  1. Apr 28, 2012 #1
    The problem: A canal cut in rock (n= 0.030) is a trapezoidal in section with a bottom width of 6.10m and the side slopes of 1 on 1. The allowable average velocity is 0.76 m/s. What slope will produce 5.66 m^3/s? The books answer is 0.000675

    from the mannings equation

    V=(1.486/n)R^2/3 x S^1/2 i get... 0.76=(1.486/0.030)? im confused on where to go
     
  2. jcsd
  3. Apr 29, 2012 #2
    Use of the Manning formula necessitates knowing the slope. But that is what is sought. So how did you do justify you did?

    Hint:
    Start out by determining the area of the open channel. Then use the Manning formula to determine the slope.
     
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