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The problem: A canal cut in rock (n= 0.030) is a trapezoidal in section with a bottom width of 6.10m and the side slopes of 1 on 1. The allowable average velocity is 0.76 m/s. What slope will produce 5.66 m^3/s? The books answer is 0.000675
from the mannings equation
V=(1.486/n)R^2/3 x S^1/2 i get... 0.76=(1.486/0.030)? I am confused on where to go
from the mannings equation
V=(1.486/n)R^2/3 x S^1/2 i get... 0.76=(1.486/0.030)? I am confused on where to go