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Flux Density and Capitance relationship?

  1. Mar 23, 2009 #1
    Is there a way to relate flux Density with capacitance (Parallel plate capacitor). Yes/ No...

    I will be thankful if you tell me the equation is there is a relationship.

    In case we cannot relate them, then is there a way to relate any electromagnetic parameter with parallel plate capacitance.

    Thanks
     
  2. jcsd
  3. Mar 23, 2009 #2
    The voltage V on a parallel capacitor = E d where E is electric field (electric flux density) and d is separation.

    C = Q/V = Q/(E d) =e0 A/d; e0 = 8.85 x 10^-12 Farads per meter
     
  4. Mar 23, 2009 #3

    Is Q= (e0 A)/E??
     
  5. Mar 23, 2009 #4
    From my last equation

    Q/V = Q/(E d) = e0A/d

    So Q = e0A E

    (or = e0A V/d or = V C)
     
  6. Mar 24, 2009 #5
    Thanks for your generous reply.

    I am getting the value of E from my simulation software. 'd' is the distance between parallel plates, which is known. But what about Q. How can find Q? from the Simulation enviroment, I can compute the following variables

    1. electric Potential
    2. Total Flux Density
    3. Total Field Intensity
    4. Current Density
    5. Inductance.

    Pl tell me some equation that can be used to calculate capacitance (parallel plate), using the parameters that can be calculated using the software (5 listed above).

    Thanks
     
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