Flux Density and Capitance relationship?

  • Thread starter Oscar6330
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Is there a way to relate flux Density with capacitance (Parallel plate capacitor). Yes/ No...

I will be thankful if you tell me the equation is there is a relationship.

In case we cannot relate them, then is there a way to relate any electromagnetic parameter with parallel plate capacitance.

Thanks
 
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The voltage V on a parallel capacitor = E d where E is electric field (electric flux density) and d is separation.

C = Q/V = Q/(E d) =e0 A/d; e0 = 8.85 x 10^-12 Farads per meter
 
The voltage V on a parallel capacitor = E d where E is electric field (electric flux density) and d is separation.

C = Q/V = Q/(E d) =e0 A/d; e0 = 8.85 x 10^-12 Farads per meter

Is Q= (e0 A)/E??
 
From my last equation

Q/V = Q/(E d) = e0A/d

So Q = e0A E

(or = e0A V/d or = V C)
Thanks for your generous reply.

I am getting the value of E from my simulation software. 'd' is the distance between parallel plates, which is known. But what about Q. How can find Q? from the Simulation enviroment, I can compute the following variables

1. electric Potential
2. Total Flux Density
3. Total Field Intensity
4. Current Density
5. Inductance.

Pl tell me some equation that can be used to calculate capacitance (parallel plate), using the parameters that can be calculated using the software (5 listed above).

Thanks
 

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