Flux integral of a curl = zero

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SUMMARY

Stokes's theorem confirms that the flux integral of the curl of a vector field over a closed surface is always zero. This is due to the absence of a boundary curve, which results in the line integral over the boundary being zero. The mathematical representation is given by the equation \(\int\int_S \nabla \times \vec F\cdot \hat n\, dS = \int\int\int_V \nabla \cdot \nabla \times \vec F\, dV= 0\), highlighting that the divergence of a curl is zero under appropriate continuity conditions. This theorem has significant implications in both mathematics and physics.

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Does Stokes's theorem imply that the flux integral of a curl of a vector field over a closed surface is always zero? (because then there is no boundary curve and thus the line integral over the boundary curve is zero)

Is there an insightful way to see why this is always true? Maybe a connection with physics or so.

Thank you,
mr vodka
 
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By the divergence theorem

[tex]\int\int_S \nabla \times \vec F\cdot \hat n\, dS = \int\int\int_V \nabla \cdot \nabla \times \vec F\, dV= 0[/tex]

because under appropriate continuity conditions the divergence of a curl is zero.
 

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