Flux through a surface Question

  • Thread starter Thread starter leext101
  • Start date Start date
  • Tags Tags
    Flux Surface
Click For Summary

Homework Help Overview

The problem involves calculating the flux of a vector field through a specified surface defined by the equation z=49-(x²+y²)² above the xy-plane. The vector field is given as F = (yz)i + (xz)j + (-17+xy)k.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using the flux through a surface equation and consider parameterizing the surface in polar coordinates. There are attempts to clarify the limits of integration and the nature of the normal vector. Some participants express confusion regarding the correct formulation of the integral and the use of normal versus tangent vectors.

Discussion Status

The discussion is ongoing, with various approaches being explored, including both polar and Cartesian coordinates. Some participants have provided calculations, while others are questioning assumptions and seeking clarification on the setup of the problem.

Contextual Notes

Participants are navigating different coordinate systems and their implications on the limits of integration. There is mention of an incorrect initial answer, prompting further exploration of the problem setup.

leext101
Messages
4
Reaction score
0

Homework Statement


Let S be the part of the surface z=49-(x2+y2)2 above the xy-plane, oriented upward.

Let vector field F= (yz) i +(xz) j + (-17+xy) k

Compute the flux of F through S.


Homework Equations


Flux through surface equation ∫s F(x,y,f(x,y)) dot product (-fx i-fy j + k) dxdy


The Attempt at a Solution


I used the equation to find flux through a surface plugging in F(x,y,(49-(x2+y2)2) for the vector field, I took the dot product. I believe the limits are -sqrt(7)≤x≤sqrt(7) and -sqrt(7)≤y≤sqrt(7). The answer I integrated out was -476 which was incorrect.

I appreciate your time and help!
 
Physics news on Phys.org
Try parameterizing the surface in polar coordinates and then use

∫∫F.n ds = ∫∫F |rrxrθ| dA
 
rock.freak667 said:
Try parameterizing the surface in polar coordinates and then use

∫∫F.n ds = ∫∫F |rrxrθ| dA
The first of these should be a single path integral, not a double integral, shouldn't it? Also I am puzzled by your "F.n". I would have used \vec{F}\cdot d\vec{s} where "d\vec{s}" is the vector tangent to the curve, not normal to it, with length ds.
 
So if I do use polar coordinates would the limits be 0≤r≤sqrt(7), 0≤θ≤2∏ and a normal vector of n= k?
 
using polar coordinates I calculated an answer -238pi
 
If I stick with cartesian coordinates would the limits be -sqrt(7)≤y≤sqrt(7) and
-sqrt(7)≤x≤sqrt≤(7)?

Thanks everyone for posting
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K