two containers are connected by a cord (of negligible mass) passing over a frictionless pulley (also of negligible mass). At time t = 0, container 1 has mass 1.30 kg and container 2 has mass 2.8 kg, but container 1 is losing mass (through a leak) at the constant rate of 0.200 kg/s. a) At what rate is the acceleration magnitude of the containers changing at t = 0? (b) At what rate is the acceleration magnitude of the containers changing at t = 3.00 s? (c) When does the acceleration reach its maximum value? [PLAIN]http://img5.imageshack.us/img5/50/q55u.jpg [Broken] Take upwards as positive Second Newton's law m1 : -m1 g + T = m1 a (1) m2: -m2 g + t = -m2 a (2) (1) - (2)--------> g(m2 - m1) = a (m1 + m2) a = g(m2 - m1) / (m1 + m2) a. t = 0 m1 = 1.3kg m2 = 2.8 kg a = 3.58 m/s^2 b. t = 3s m1 = 1.3 - 3 * 0.2 = 0.7 kg m2 = 2.8 kg a = 5.88 m/s^2 c. Ok, I don't know how to do this part. I believe that in order to get max. acceleration, m1 must be = 0, so a will be equal to g ??? is that correct ???