Force and Motion with two unknows

In summary, we have two bodies, A and B, with masses of 100 N and 77 N, respectively. The coefficient of friction between A and the incline is μs = 0.52 and the coefficient of kinetic friction is μk = 0.28. The angle θ is 31° and the positive direction of the x-axis is down the slope. We have two equations, one for each body, but we also have two unknowns: tension and acceleration. Substituting and solving for these unknowns may help solve the problem.
  • #1
ankitp3
3
0
Body A in Fig. 6-36 weighs 100 N, and body B weighs 77 N. The coefficients of friction between A and the incline are μs = 0.52 and μk = 0.28. Angle θ is 31°. Let the positive direction of an x-axis be down the slope. What is the acceleration of A if A is initially (a) at rest, (b) moving up the incline, and (c) moving down the incline?
http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c06/fig06_34.gif

=S m stuck @ -FT + mgsintheta = ma and i am stuck with two unknowns.. Tension and acceleration
 
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  • #2
Welcome to PF!

ankitp3 said:
-FT + mgsintheta = ma and i am stuck with two unknowns.. Tension and acceleration

Hi ankitp3! Welcome to PF! :smile:

Yes, you do have two unknowns.. tension and acceleration …

but you also have two equations, one for body A and one for body B. :wink:
 
  • #3


still having hard time solving this problem :S
 
  • #4
ankitp3 said:
still having hard time solving this problem :S

ok, show us your two equations, and we'll see what we can do … :smile:
 
  • #5
FK + mgsingtheta - FT = m1ax (block A)

Ft - Fg = m2gy (block b)

ukmgcostheta - mgsintheta - FT = m1ax

Ft - (wB) = (wB/9.8)a

ukmgcostheta + mgsintheta - Ft (< sub in Ft from the last equation)
 
  • #6
ankitp3 said:
FK + mgsingtheta - FT = m1ax (block A)

Ft - Fg = m2gy (block b)

ukmgcostheta - mgsintheta - FT = m1ax

Ft - (wB) = (wB/9.8)a

ukmgcostheta + mgsintheta - Ft (< sub in Ft from the last equation)

Sorry … I've stared at this for several minutes and I can't follow it. :confused:

Can you put the numbers in? :smile:
 

1. What is the formula for calculating force and motion with two unknowns?

The formula for calculating force and motion with two unknowns is F = ma, where F is force, m is mass, and a is acceleration. This formula is also known as Newton's second law of motion.

2. How do you find the acceleration of an object when both force and mass are unknown?

In order to find the acceleration of an object when both force and mass are unknown, you will need to rearrange the formula F = ma. If you know the mass and force acting on the object, you can solve for acceleration by dividing the force by the mass.

3. Can you determine the force acting on an object if its mass and acceleration are known?

Yes, you can determine the force acting on an object if its mass and acceleration are known by using the formula F = ma. Simply multiply the mass of the object by its acceleration to find the force.

4. How does the direction of force affect an object's motion?

The direction of force has a significant impact on an object's motion. If the force is applied in the same direction as the object is moving, it will increase the speed of the object. However, if the force is applied in the opposite direction, it will cause the object to slow down or even change direction.

5. What is the difference between balanced and unbalanced forces in relation to motion?

Balanced forces refer to the situation where the forces acting on an object are equal in size and opposite in direction, resulting in no change in the object's motion. On the other hand, unbalanced forces occur when the forces acting on an object are not equal, causing the object to accelerate in the direction of the larger force.

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