Force due to Solar Radiation and Gravity

AI Thread Summary
The discussion revolves around calculating the equilibrium radius of a spherical particle in space, balancing gravitational and solar radiation forces. The gravitational force is expressed using Newton's law of gravitation, while the solar force is derived from solar intensity and the particle's cross-sectional area. A key point raised is the validity of the mass calculation, questioning whether mass decreases as volume increases. Additionally, a participant notes that the solar constant was not correctly incorporated in the calculations. The final calculation yielded a radius of approximately 790,238.5 meters, but concerns about the methodology and equations used were highlighted.
Mnemonic
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Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)

F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
 
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Mnemonic said:

Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)
Check that formula. Does mass really get smaller as the volume of the material gets larger?
F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
Nope. Besides the issue with the mass expression noted above, I don't see where the solar constant S is involved in your calculation.
 
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