Force exerted by water in a U-shaped tube

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In a U-shaped tube with water flowing at a constant velocity v and flow rate u, the force exerted by the water on the wall is derived from the change in momentum. The calculation shows that the change in momentum is 2uvΔt, leading to the conclusion that the force F equals 2uv. This solution is confirmed as correct by participants in the discussion. The interaction highlights the relationship between flow rate, velocity, and the resulting force on the tube walls. Understanding these principles is essential for analyzing fluid dynamics in similar systems.
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Homework Statement


In a U-shaped tube, water is flowing with velocity v. The flowing rate is u, and it's constant. What force does the water exert on the wall of the tube.

Homework Equations



F = dp/dt

u = m/t

The Attempt at a Solution


The change in momentum is
mv - (-mv)

or

2uv \Delta t

so

F = 2uv

is this correct?
 
Last edited:
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Yes, that's correct.
 
Thanks a lot !:biggrin:
 
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