Force exerted on a seat on rollercoaster

AI Thread Summary
The discussion revolves around calculating the force exerted on a passenger seat at the top of a rollercoaster loop, given a hill height of 55m and a loop radius of 20m. Participants clarify the correct method to find the velocity using conservation of energy, resulting in a velocity of approximately 32.83 m/s. The net force equation is debated, with emphasis on correctly applying Fnet = Fg + Fn rather than including additional forces. The initial calculations led to an incorrect force of 1500N, prompting a reevaluation of the steps taken. Ultimately, the focus is on accurately determining the forces acting on the rollercoaster at the loop's apex.
annamae
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Homework Statement


We have a general rollercoaster design- a hill and a perfect circle loop,
the hill is 55m high and the loop has a radius of 20m. What is the force exerted on the passenger seat at the very top of the loop?
a. 300
b. 500
c. 750
d. 1000
e. 0

Homework Equations


ac=v2/r
Fnet=Fg+Fn+Fp+Ff

The Attempt at a Solution


I found centripetal acceleration to be 15 m/s2
The velocity is 17.32 m/s
Fnet= 60(9.8)+60(15)
But my final answer is 1500N which isn't one of the above choices
So what am i doing wrong?
 
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How did you get that velocity? since v=(2gh)^0.5, you get v=32.833 m/s. Also, what's the mass of the roller-coaster?
 
zush said:
How did you get that velocity? since v=(2gh)^0.5, you get v=32.833 m/s.
No, use conservation of energy between the top of the hill and the top of the loop to find v
Also, what's the mass of the roller-coaster?
Looks like it's 60 kg, from the OP's calc..which was left out of the problem statement.

annamae said:

Homework Statement


We have a general rollercoaster design- a hill and a perfect circle loop,
the hill is 55m high and the loop has a radius of 20m. What is the force exerted on the passenger seat at the very top of the loop?
a. 300
b. 500
c. 750
d. 1000
e. 0

Homework Equations


ac=v2/r
Fnet=Fg+Fn+Fp+Ff

The Attempt at a Solution


I found centripetal acceleration to be 15 m/s2
Yes, how did you arrive at this?
The velocity is 17.32 m/s
yes,how did you arrive at this?
Fnet= 60(9.8)+60(15)
No, Fnet = Fg + Fn, you have written Fnet = Fg + ma
But my final answer is 1500N which isn't one of the above choices
So what am i doing wrong?
Fnet = Fg + Fn = mv2/r, solve for Fn, which is what the problem is asking.
 
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