Force of wire in a magnetic field

AI Thread Summary
The discussion focuses on calculating the force exerted on a wire with a current of 2.97 A at an angle of 37.4° in a magnetic field of 0.889 T. The formula used is F = ILBsin(theta), where the values for current, length, and magnetic field are provided. The user initially calculates the force as -1.867 N but suspects an error, particularly with the sine function. It is noted that the calculator may be in radian mode, which could lead to incorrect results. The thread concludes with the user expressing gratitude for any assistance in resolving the issue.
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Homework Statement



A wire with a current of 2.97 A is at an angle of 37.4° relative to a magnetic field of 0.889 T. Calculate the force exerted on a 2.40 m length of the wire.

Homework Equations



F= ILBsin(theta)

The Attempt at a Solution



I'm under the impression that the problem gives me all the information i need, so:

F - The force I need to find
I - The given current 2.97A
L - Length of wire - 2.4m
B - .889T
sin(37.4) = -.2948 (Could my mistake be here?)

I multiply all of these values together (2.97A)(2.4m)(.889T)(-.2948) and i get = -1.867N, which isn't correct... any suggestions?
 
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Your calculator is in radian mode. That's all.
 
Thanks very much, problem solved!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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