Force on a ferrous object inside a non-uniform magnetic field

In summary, the conversation discusses how to compute the force applied on ferromagnetic material inside a non-uniform magnetic field. The suggested method involves magnetizing the material and using Lorentz law to compute the induced currents. The use of programs like FEMM is also mentioned and an example of a simple problem is given. The conversation also mentions using the magnetic potential to compute the force and discusses the possibility of omitting elastic forces on the iron cylinder.
  • #1
EnEE
16
3
Hello everyone!

I want to know how to compute the force applied on ferrous inside a non-uniform magnetic field, to make it easier, let's assume that the field direction is constant, and the magnitude decreases linearly.

Now, I know that ferromagnetic material inside a magnetic field will become magnetized, and once he become magnetized, I can compute the induced currents on the surface and inside the matter(curl of M, and Mxn, where M is the magnetization), and therefore I can use Lorentz law to compute the force.
Is that right to do this?

I saw that usually engineers using programs like FEMM to solve such problems, and I try to figure out how to solve it analytically

simple examples:
http://uzzors2k.4hv.org/index.php?page=magneticlevitation - the force applied should be similar to this:
https://en.wikipedia.org/wiki/Force_between_magnets#Force_between_two_cylindrical_magnets

simple problem:
assume we have an air-core solenoid produces a magnetic field(instead of the iron-core in the example), I want to know what is the minimum number of turns or the minimum current I need to pull a given iron cylinder (given distance from the solenoid, and given mass, and for simplify the problem I can assume that the cylinder is right in the symetric axis of the solenoid)
 
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  • #2
OK, few thougths...
1.my first thougth about induced currents and lorentz law will not work here
2.If I will use the magnetic potential: μm=0.5⋅μ⋅H⋅H
I can compute the force by F=-∇μm

H is function of z, so F is also function of z. If I omit ellastic forces on the iron cylinder(can I? maybe tension?)
I will get: F=-∫∇μm between z1 and z2(z2-z1 is the length of the cylinder)

what do you think?
 

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