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Force on dog's head out of car sunfoof

  1. Jan 15, 2015 #1
    (i have made this thread as i previously had it in the aero section and it was probably not getting the attention such an important question deserves.)

    lets use the sunroof as an example for simplicity.
    what force is the wind acting on the dog at 50mph/22.3m/s?
    dog head diameter = 0.2m
    therefore frontal area of dog head is 0.0314m^2
    Drag coefficient = 2
    air density = 1.22

    here is my attempt (#1) based on wall loading calculations:
    0.00256 * 50 * 50 = 6.4 lb/ sq feet = 306.4Pa

    0.0314 * 306.4 * 2=19.25N

    here is my attempt (2) based on drag equation
    2 x ((1.22 x 50^2)/2) * 0.0314 = 19N


    any thoughts
     
  2. jcsd
  3. Jan 15, 2015 #2

    SteamKing

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    Yayyy! They're approximately equal.
     
  4. Jan 15, 2015 #3

    billy_joule

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    But both equally wrong unfortunately! You need to use the correct units in the drag equation, mph won't do. Also, 2 for Cd seems high for a dogs head, where did you get that from?
     
  5. Jan 17, 2015 #4
    The tongue flapping contributes to an anamalous CD value.
     
  6. Jan 22, 2015 #5
    the first is correct units, but the second should read
    2 x ((1.22 x 22.352^2)/2) * 0.0314 = 19N

    yes, i agree on the 2 cd, perhaps its the engineering factor of safety.
     
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