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**[SOLVED] Force Problem**

A 4.0kg block is put on top of a 5.0 kg block. The coefficient of static friction between the two blocks is u = 0.23 . The assembly of blocks is placed on a horizontal, frictionless table. What is the magnitude of the maximum horizontal force F that can be applied to the lower block so that the blocks will move together without any slippage?

The only relevant equations I can think of are

F = ma and

F = uN

I assumed that if the blocks are moving together than the fictional force between the blocks is greater than or equal to the forward force on the bottom block. I got that the maximum static frictional force is F = (.23)(4.0 * 9.8) = 9.016N but I don't know where to go from there, any ideas? Thanks