- #1
canucks
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We are doing a study & our calculated force is MUCH higher than our data. I'm wondering if our calculation is right.
how much force it would take to stop a person in a wheelchair (83kg) going 6km/hr and stopping in 10 cm or within 2 sec. as an example?
This is my calculation..Am I on the right track? F= ma We can find a using v=at+v0 so a=v/t so (1.67)/(2) = .835 ( v0=0 which treadmill initial speed) So f= 83*.835= 69.35 N
If you want to find it at 10cm (.1m ) you can use conservation energy formula as well Fd = 1/2 mv 2 so mad=1/2mv2so a= v2/2d so in this case a=1.672/.1= 13.94 m/s so F = 8313.94=1157.39 N
how much force it would take to stop a person in a wheelchair (83kg) going 6km/hr and stopping in 10 cm or within 2 sec. as an example?
This is my calculation..Am I on the right track? F= ma We can find a using v=at+v0 so a=v/t so (1.67)/(2) = .835 ( v0=0 which treadmill initial speed) So f= 83*.835= 69.35 N
If you want to find it at 10cm (.1m ) you can use conservation energy formula as well Fd = 1/2 mv 2 so mad=1/2mv2so a= v2/2d so in this case a=1.672/.1= 13.94 m/s so F = 8313.94=1157.39 N