Force & Torque Homework: 10kg Plank on Wall/Floor

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Homework Statement


A 10 kg plank leans against a frictionless wall and floor at an angle of 60 degrees with the horizontal. A horizontal rope connects the center of mass of this uniform plank with the wall.
a- Use dynamics to find the normal force between the floor and the plank.
b- Find the normal force between the wall and the plank.
c- Determine the tension in the rope.
d- Show the net torque is zero when the pivot is located where the plank meets the wall.


Homework Equations



torque = Fsin(phi) radius

The Attempt at a Solution


a- normal floor = weight = 10kg (9.8) = 98 N
b- Using torque, I end up with -56.6.

-torque of normal floor + torque of normal wall = 0
98 N (sin 210) length/2 = normal wall (sin 120) length /2

normal wall = -56.6
What am I doing wrong?
 
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veronicak5678 said:

Homework Statement


A 10 kg plank leans against a frictionless wall and floor at an angle of 60 degrees with the horizontal. A horizontal rope connects the center of mass of this uniform plank with the wall.
a- Use dynamics to find the normal force between the floor and the plank.
b- Find the normal force between the wall and the plank.
c- Determine the tension in the rope.
d- Show the net torque is zero when the pivot is located where the plank meets the wall.


Homework Equations



torque = Fsin(phi) radius

The Attempt at a Solution


a- normal floor = weight = 10kg (9.8) = 98 N
b- Using torque, I end up with -56.6.

-torque of normal floor + torque of normal wall = 0
98 N (sin 210) length/2 = normal wall (sin 120) length /2

normal wall = -56.6
What am I doing wrong?

Using the point where the plank rests on the ground as the point of rotation, a torque due to tension and one due to gravity act in the negative direction, both of which are negated by a normal force imposed upon the plank by the wall in the clockwise direction. Does this help?
 
If I use that as the rotation spot, I don't think I will have enough info to solve. I don't know the tension force or the length of the plank. I was using the center as the pivot to avoid lookig at tension and weight.
 
I tried using that spot and this is what i came up with:

torque tension + torque weight - torque normal floor = 0
56.6 N * sin 240 * length/2 + 98 N * sin 150 * length/2 - 98 N * sin 210 * length = 0

But this equation leaves me with 49N * length, not 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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