(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A high diver of mass 83.0 kg jumps off a board 10.0 m above the water. If his downward motion is stopped 1.90 s after he enters the water, what average upward force did the water exert on him?

2. Relevant equations

[tex]\sum[/tex]Forces = ma

X=X[tex]_{0}[/tex]+V[tex]_{i}[/tex]+1/2at

3. The attempt at a solution

the total force exerted by the diver on the water is:

[tex]\sum[/tex]Forces = 83kg*9.8 (gravitational acceleration) = 813.4N

then with the given time.. i don't know how to solve for the upward force

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# Forces, action and reaction pairs

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