Find Value of tan φ of Reaction Force | Isaac Physics

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Homework Help Overview

The discussion revolves around finding the value of tan φ, where φ is the angle made by the line of action of the reaction force at a hinge above the horizontal. The context involves a uniform trapdoor held open at an angle θ=60° to the horizontal, with gravitational effects considered.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss simultaneous equations related to forces acting on the trapdoor, specifically Fcosθ + Nsinθ = mg and Fsinθ = Ncosθ. There is uncertainty about the angles involved, with some questioning whether certain angles should be φ instead of θ. Additionally, the need for a torque balance equation is mentioned.

Discussion Status

Participants are exploring different interpretations of the equations and the roles of the angles involved. Some have pointed out the necessity of considering torque balance, while others express confusion about which values to use in the equations. There is no explicit consensus, but the discussion is progressing with various angles of reasoning being examined.

Contextual Notes

Participants note that φ does not depend on the mass or gravitational strength, and that θ is provided as a known value. The discussion highlights the presence of three unknowns: F/mg, N/mg, and φ, which complicates the problem-solving process.

ephphatha16
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Find the value of tan φ to 2 sf where φ is angle made by line of action of reaction force at hinge above horizontal.
https://isaacphysics.org/questions/trapdoor_num
Part B Angle of reaction force

Homework Equations


  • Mass of uniform trapdoor: m=4.0kgm=4.0kg
  • The trapdoor is held open making an angle θ=60∘θ=60∘ to the horizontal.
Information assumed
- Magnitude of the gravitational field strength, g=9.81ms−2

The Attempt at a Solution


[/B]Don't know how to move on with this simultaneous equation

Fcosθ + Nsinθ=mg
Fsinθ = Ncosθ
 

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ephphatha16 said:
Fcosθ + Nsinθ=mg
Fsinθ = Ncosθ
Shouldn't some of those angles be φ?
You will also need to consider torque balance.
 
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haruspex said:
Shouldn't some of those angles be φ?
You will also need to consider torque balance.
Yeah true

Fcos θ + Nsin φ = mg
F sin θ = N cos φ

But I don't know what values to plug in ... is the first equation about vertical component and the second equation about horizontal component?
 
ephphatha16 said:
I don't know what values to plug in
φ will not depend on m or g. You are given a value for θ.
ephphatha16 said:
is the first equation about vertical component and the second equation about horizontal component?
Yes, but you have three unknowns, F/mg, N/mg and φ. You need a torque balance equation.
 
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