Forces during the motion of an object in a vertical circle

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SUMMARY

The discussion focuses on the dynamics of an object in vertical circular motion, specifically at point D where the normal force (R) is assumed to be zero. The equation R + W = mv²/r is used to analyze the forces, where W represents weight and mv²/r denotes centripetal force. It is established that at R=0, gravity alone provides the necessary centripetal force, allowing the object to maintain circular motion without contact. This scenario is likened to a satellite in orbit, emphasizing the critical speed of √(rg) for sustained motion.

PREREQUISITES
  • Understanding of centripetal force and its equation mv²/r
  • Knowledge of gravitational force and its role in circular motion
  • Familiarity with normal forces and their significance in contact scenarios
  • Basic principles of motion in physics, particularly in vertical circles
NEXT STEPS
  • Study the implications of R=0 in vertical circular motion scenarios
  • Explore the concept of minimum speed for maintaining circular motion
  • Learn about gravitational forces acting on objects in different motion contexts
  • Investigate the behavior of satellites and their orbital mechanics
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of motion in vertical circles and the dynamics of forces acting on objects in such scenarios.

influx
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At D, by resolving and equating to centripetal force we know that R + W = mv^2/r, however, why do we assume R=0? Based on what?

I know my post is short and usually a longer solution is required but I do not have a problem with the maths in the attached, it's just the concept of letting R=0 that I need clarified.

Thanks
 
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influx said:
View attachment 81979View attachment 81980

At D, by resolving and equating to centripetal force we know that R + W = mv^2/r, however, why do we assume R=0? Based on what?

I know my post is short and usually a longer solution is required but I do not have a problem with the maths in the attached, it's just the concept of letting R=0 that I need clarified.

Thanks
Based on the fact that normal forces are contact forces perpendicular to the tangent of the curve that in this instance must push on the object. If it is less than 0, contact is lost. So it must push with a value greater than 0. Problem is looking for minimums.
 
PhanthomJay said:
Based on the fact that normal forces are contact forces perpendicular to the tangent of the curve that in this instance must push on the object. If it is less than 0, contact is lost. So it must push with a value greater than 0. Problem is looking for minimums.

What happens at exactly R=0? It remains in a circular motion?
 
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influx said:
What happens at exactly R=0? It remains in a circular motion?
Yes, gravity only supplies the centripetal force without contact at that point D. The pellet remains at a distance 2 feet from the center of the circle without 'dropping', even though contact is momentarily lost, and with a speed of \sqrt{rg}. It behaves like a satellite in orbit at that specific point, no contact necessary at that point. If the speed was less than that, then continuous circular motion could no be maintained.
 
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