Formal proof of Thevenin theorem

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SUMMARY

The forum discussion centers on the formal proof of Thevenin's theorem, emphasizing the equivalence of any linear network viewed from a port to a linear bipole. Participants discuss the application of linear algebra, specifically Gauss elimination, to demonstrate how a composite network can be simplified into two parts, leading to Thevenin or Norton equivalents. The conversation highlights the importance of understanding the underlying linear system structure to validate the theorem's proof.

PREREQUISITES
  • Understanding of Thevenin's theorem
  • Familiarity with linear algebra concepts, particularly Gauss elimination
  • Knowledge of linear networks and bipoles
  • Basic principles of circuit theory
NEXT STEPS
  • Research formal proofs of Thevenin's theorem
  • Study linear algebra applications in electrical engineering
  • Explore Norton’s theorem and its relationship to Thevenin’s theorem
  • Learn about circuit simplification techniques using Gauss elimination
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Electrical engineers, circuit designers, and students studying circuit theory who seek a deeper understanding of Thevenin's theorem and its mathematical foundations.

cianfa72
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TL;DR
Formal proof of Thevenin theorem from an algebraic point of view
Hi,
I am looking for a formal proof of Thevenin theorem. Actually the first point to clarify is why any linear network seen from a port is equivalent to a linear bipole.

In other words look at the following picture: each of the two parts are networks of bipoles themselves.
Thevenin.jpg

Why the part 1 -- as seen from the interconnection's port (topological cut) -- is equivalent to a linear bipole itself ?

Thank you.
 
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Have you tried a google search? I did "proof of thevenin's theorem pdf" and got so much good stuff I honestly don't know which one to link to here. Many have references to other papers too.
 
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DaveE said:
Have you tried a google search? I did "proof of thevenin's theorem pdf" and got so much good stuff I honestly don't know which one to link to here.
Yes, I believe the point is to show - from a linear algebraic point of view - that the linear system of the complete composite network actually breaks in two parts: by mean of elimination (e.g. Gauss elimination) we may always reduce each part to a linear equation (the Thevenin or Norton equivalent).
 
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@cianfa72 did you mean to post this in another thread? As it stands now, this makes no sense.
 
jim mcnamara said:
@cianfa72 did you mean to post this in another thread?
No, I mean whether or not you can confirm my argument about the structure of the linear system and how to break it in the two parts involved.
 
Thanks for the clarity.
 

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