Finding Thevenin Equiv for Circuit w/ R1, R2, R3, R4, R5

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Discussion Overview

The discussion focuses on finding the Thevenin equivalent for a circuit involving multiple resistors (R1, R2, R3, R4, R5) and a voltage source (VDC). Participants explore methods for calculating the equivalent resistance and voltage, addressing both analytical and simulation approaches.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about finding the Thevenin equivalent and outlines their approach to calculating the equivalent resistance.
  • Another participant requests clarification on how the simulation results differ from the analytical calculations.
  • A participant suggests that the equivalent voltage source must also be calculated to complete the Thevenin equivalent circuit.
  • Values for the resistors and voltage source are provided, along with calculations for the equivalent resistances.
  • One participant points out a discrepancy in the calculations and questions why the correct equivalent resistance was ignored in further calculations.
  • Another participant offers guidance on how to determine the Thevenin voltage and resistance using the simulation results.
  • A later reply indicates that the original poster feels more confident in finding the Thevenin voltage and resistance after receiving assistance.

Areas of Agreement / Disagreement

Participants express differing views on the calculations and methods used to find the Thevenin equivalent, with no consensus reached on the correct approach or results. Discrepancies between simulation and analytical results remain unresolved.

Contextual Notes

Limitations include potential misunderstandings in the calculation steps and dependencies on the accuracy of the simulation setup. The discussion does not resolve the discrepancies between the analytical and simulation results.

DmytriE
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Hi All,

I am struggling to find the thevenin equivalent for the following circuit. I will leave out the values for the resistances because they don't really matter in this case. I'm looking for guidance on how to find the overall thevenin.

I know the R-Thevenin is the same as the R-equivalent for the circuit. So I approached the problem as I would to find the equivalent for any other circuit.

R1 is parallel with R2. So This new resistance would be (R1 * R2)/ (R1 + R2). Let's call this new resistance R12

This next part is where I get confused. I believe that R3, R12, and R5 are all in series with one another so you can add their resistances. and this new resistance would be in parallel with R4.

I then simulate the circuit using PSpice and I do not get the same answer as the simulation. Any help would be greatly appreciated!

https://docs.google.com/file/d/0B70IRvZhJgh0UDAxaWowN0tIYkU/edit?usp=sharing
 
Last edited by a moderator:
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I cannot access the shared circuit diagram I guess?
 
Rudinhoob said:
I cannot access the shared circuit diagram I guess?

I have now fixed the problem. Everyone should be able to access it. Thanks for the heads up.
 
Could you please show how your simulation and analytical solution differ?

Edit: Just a thought, but did you calculate the equivalent voltage source as well that's needed to form the complete Thévenin equivalent circuit?
 
Last edited:
Here are the values for each resistor:
R1: 5.6k, R2: 12k, R3: 2.2k, R4: 15k, R5: 1k
VDC: 12V

R1 || R2 = 3.818k
R3, R12, R5 are all in series: 7.018k
R3.12.5 || R4: 4.781k

https://docs.google.com/file/d/0B70IRvZhJgh0eTdxZ2ZVeS1aamc/edit?usp=sharing

RTh = Vin / I1
I1 = 935uA
RTh = 12V / 935uA = 12.830k

There is a discrepancy of approximately 2.5 - 3 times...
 
Last edited by a moderator:
Very strange. You have done an admirable job of calculating the correct equivalent resistance (4.781K) and then for some reason you have ignored it and gone on to calculate an incorrect equivalent resistance. Why?
 
If you want to use your simulation to check your calculation of the equivalent resistance then:

- The equivalent voltage, Vth, is equal to V_O when the output is an open circuit.

Thus Vth = 15e3*371.6e-6 V = 5.574 V.

- Rth = Vth/I_O when the output is a short circuit.

Thus, in your simulation, you need to short out R4 and measure the current through R3/R5. Vth divided by this current is your equivalent resistance.
 
Thank you very much! I was having trouble understand how to find Vth. With your help and some help of my classmate I feel confident in finding VTh and RTh.
 

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