Formation of 17O Nucleus from 14N + Alpha Particle

AI Thread Summary
The discussion centers on the nuclear reaction involving the bombardment of a 14N nucleus with an alpha particle, resulting in the formation of a 17O nucleus and the emission of a particle. The options for the emitted particle include a neutron, proton, electron, or positron, with the correct answer identified as a proton. The reasoning involves balancing mass numbers and considering nuclear charge, as options involving electrons and positrons do not maintain mass balance. The atomic numbers of the involved nuclei (Nitrogen, Oxygen, and Helium) are essential for understanding the reaction dynamics. Clarification on atomic numbers helps resolve the confusion regarding why only a proton is the acceptable emitted particle.
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Homework Statement


An alpha particle is bombarded on 14
N. As a result a 17
O nucleus is formed, and a particle is emitted. This particle is a: (a) neutron (b) proton (c) electron (d) positron. The answer is given as (b).

Homework Equations


The solution must take into account that the mass numbers have to balance on both sides of the equation.


The Attempt at a Solution



(c) and (d) get ruled out because they do not lead to a balance in mass numbers. Since the balance would be possible for both options (a) and (b) I need some clues as to why only (b) is acceptable.
 
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What about the nuclear charge?
 
The mass number alone does not give an indication of the charge. The problem does not state the atomic numbers. Had this been given the question of my doubt would not have arisen. Looking forward to further inputs from you. Thanks.
 
The problem does not give the atomic numbers directly, but it tells you that the three nuclei are Nitrogen, Oxygen, and Helium (alpha particle). From this information you know the atomic numbers.
 
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