Formula for Interplanar Distance in Cubic Lattice

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i am trying to find the formula for the inter-planar distance for the cubic .
i do know that it's :d (h,k,l)= a /√ (h² +k²+l²), i am only able to get to : 2π/(√a*²(h²+k²+l²)) , with a* being the parameter of the reciprocal lattice , the explanation given to how to go from a* to a , is that for all cubic lattices : a* = 2π/a , and this is what i don t understand , a = a* , only in the case of the simple cube , for body centered cube for example : we find a* = (2π/a)( j+k )with a*, j,k vectors ,a : parameter of the elementary lattice ; so calculating the modulus we find a*= √2 2π/a ;
and i am feeling frustrated , i know i am missing something but i don t know what .
 
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It looks like you need to clarify the definitions of a and a*.
 
a refers to the parameter of the elementary lattice , as a, b, c , of the simple cubic lattice .
Diagram of a parallelepiped unit cell with origin at the lower back corner, axes x, y and z, edge vectors a, b and c, and angles alpha, beta and gamma marked between the edges.

a* is the parameter of the reciprocal lattice , as in a* , b* , c* .
Slide titled 'Reciprocal lattice of FCC is BCC' showing FCC primitive vectors a1, a2, a3 and the reciprocal vector b1 formula, with b2 and b3 below, concluding BCC reciprocal lattice with lattice constant 4π/a.

a* , b* , c* are deduced from the parameters of the primitive lattice, a1 , a2 and a3 .
in the second pic a* is b1 , b*is b2 , c* is b3 , .
you can see that the modulus of a* = b 1 , is not 2π/a .
 
after a lot of searching , i noticed something , they do not actually mention the modulus of the vectors themselves but the lattice constant , i don t exactly understand what the difference is .
lattice constant is defined as the physical dimension of unit cells in a crystal lattice. so how is that different from the modulus of the lattice vector ?
 
i think i finally understood what is going on : you see i have always assumed that they were talking about the primitive vectors , for example to calculate the reciprocal vectors in the case of body centered we had to look for the primitive lattice ( which is a simple cube ) , but doing that means we re calculating the primitive reciprocal vectors . not just the reciprocal vectors .
and so if we actually try to calculate the reciprocal vectors of the actual body centered lattice,without going through the primitive lattice , we find 2π/a , and that is true for all cubic lattices .
uhhhh finally . all because of one word : primitive .